Optimal. Leaf size=115 \[ \frac{(1-2 x)^{5/2}}{2 (3 x+2)^2 \sqrt{5 x+3}}+\frac{55 (1-2 x)^{3/2}}{4 (3 x+2) \sqrt{5 x+3}}-\frac{1815 \sqrt{1-2 x}}{4 \sqrt{5 x+3}}+\frac{1815}{4} \sqrt{7} \tan ^{-1}\left (\frac{\sqrt{1-2 x}}{\sqrt{7} \sqrt{5 x+3}}\right ) \]
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Rubi [A] time = 0.0287101, antiderivative size = 115, normalized size of antiderivative = 1., number of steps used = 5, number of rules used = 3, integrand size = 26, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.115, Rules used = {94, 93, 204} \[ \frac{(1-2 x)^{5/2}}{2 (3 x+2)^2 \sqrt{5 x+3}}+\frac{55 (1-2 x)^{3/2}}{4 (3 x+2) \sqrt{5 x+3}}-\frac{1815 \sqrt{1-2 x}}{4 \sqrt{5 x+3}}+\frac{1815}{4} \sqrt{7} \tan ^{-1}\left (\frac{\sqrt{1-2 x}}{\sqrt{7} \sqrt{5 x+3}}\right ) \]
Antiderivative was successfully verified.
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Rule 94
Rule 93
Rule 204
Rubi steps
\begin{align*} \int \frac{(1-2 x)^{5/2}}{(2+3 x)^3 (3+5 x)^{3/2}} \, dx &=\frac{(1-2 x)^{5/2}}{2 (2+3 x)^2 \sqrt{3+5 x}}+\frac{55}{4} \int \frac{(1-2 x)^{3/2}}{(2+3 x)^2 (3+5 x)^{3/2}} \, dx\\ &=\frac{(1-2 x)^{5/2}}{2 (2+3 x)^2 \sqrt{3+5 x}}+\frac{55 (1-2 x)^{3/2}}{4 (2+3 x) \sqrt{3+5 x}}+\frac{1815}{8} \int \frac{\sqrt{1-2 x}}{(2+3 x) (3+5 x)^{3/2}} \, dx\\ &=-\frac{1815 \sqrt{1-2 x}}{4 \sqrt{3+5 x}}+\frac{(1-2 x)^{5/2}}{2 (2+3 x)^2 \sqrt{3+5 x}}+\frac{55 (1-2 x)^{3/2}}{4 (2+3 x) \sqrt{3+5 x}}-\frac{12705}{8} \int \frac{1}{\sqrt{1-2 x} (2+3 x) \sqrt{3+5 x}} \, dx\\ &=-\frac{1815 \sqrt{1-2 x}}{4 \sqrt{3+5 x}}+\frac{(1-2 x)^{5/2}}{2 (2+3 x)^2 \sqrt{3+5 x}}+\frac{55 (1-2 x)^{3/2}}{4 (2+3 x) \sqrt{3+5 x}}-\frac{12705}{4} \operatorname{Subst}\left (\int \frac{1}{-7-x^2} \, dx,x,\frac{\sqrt{1-2 x}}{\sqrt{3+5 x}}\right )\\ &=-\frac{1815 \sqrt{1-2 x}}{4 \sqrt{3+5 x}}+\frac{(1-2 x)^{5/2}}{2 (2+3 x)^2 \sqrt{3+5 x}}+\frac{55 (1-2 x)^{3/2}}{4 (2+3 x) \sqrt{3+5 x}}+\frac{1815}{4} \sqrt{7} \tan ^{-1}\left (\frac{\sqrt{1-2 x}}{\sqrt{7} \sqrt{3+5 x}}\right )\\ \end{align*}
Mathematica [A] time = 0.0427174, size = 74, normalized size = 0.64 \[ \frac{1815}{4} \sqrt{7} \tan ^{-1}\left (\frac{\sqrt{1-2 x}}{\sqrt{7} \sqrt{5 x+3}}\right )-\frac{\sqrt{1-2 x} \left (16657 x^2+21843 x+7148\right )}{4 (3 x+2)^2 \sqrt{5 x+3}} \]
Antiderivative was successfully verified.
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Maple [B] time = 0.012, size = 202, normalized size = 1.8 \begin{align*} -{\frac{1}{8\, \left ( 2+3\,x \right ) ^{2}} \left ( 81675\,\sqrt{7}\arctan \left ( 1/14\,{\frac{ \left ( 37\,x+20 \right ) \sqrt{7}}{\sqrt{-10\,{x}^{2}-x+3}}} \right ){x}^{3}+157905\,\sqrt{7}\arctan \left ( 1/14\,{\frac{ \left ( 37\,x+20 \right ) \sqrt{7}}{\sqrt{-10\,{x}^{2}-x+3}}} \right ){x}^{2}+101640\,\sqrt{7}\arctan \left ( 1/14\,{\frac{ \left ( 37\,x+20 \right ) \sqrt{7}}{\sqrt{-10\,{x}^{2}-x+3}}} \right ) x+33314\,{x}^{2}\sqrt{-10\,{x}^{2}-x+3}+21780\,\sqrt{7}\arctan \left ( 1/14\,{\frac{ \left ( 37\,x+20 \right ) \sqrt{7}}{\sqrt{-10\,{x}^{2}-x+3}}} \right ) +43686\,x\sqrt{-10\,{x}^{2}-x+3}+14296\,\sqrt{-10\,{x}^{2}-x+3} \right ) \sqrt{1-2\,x}{\frac{1}{\sqrt{-10\,{x}^{2}-x+3}}}{\frac{1}{\sqrt{3+5\,x}}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A] time = 2.84531, size = 193, normalized size = 1.68 \begin{align*} -\frac{1815}{8} \, \sqrt{7} \arcsin \left (\frac{37 \, x}{11 \,{\left | 3 \, x + 2 \right |}} + \frac{20}{11 \,{\left | 3 \, x + 2 \right |}}\right ) + \frac{16657 \, x}{18 \, \sqrt{-10 \, x^{2} - x + 3}} - \frac{52169}{108 \, \sqrt{-10 \, x^{2} - x + 3}} + \frac{343}{54 \,{\left (9 \, \sqrt{-10 \, x^{2} - x + 3} x^{2} + 12 \, \sqrt{-10 \, x^{2} - x + 3} x + 4 \, \sqrt{-10 \, x^{2} - x + 3}\right )}} + \frac{833}{12 \,{\left (3 \, \sqrt{-10 \, x^{2} - x + 3} x + 2 \, \sqrt{-10 \, x^{2} - x + 3}\right )}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 1.83003, size = 298, normalized size = 2.59 \begin{align*} \frac{1815 \, \sqrt{7}{\left (45 \, x^{3} + 87 \, x^{2} + 56 \, x + 12\right )} \arctan \left (\frac{\sqrt{7}{\left (37 \, x + 20\right )} \sqrt{5 \, x + 3} \sqrt{-2 \, x + 1}}{14 \,{\left (10 \, x^{2} + x - 3\right )}}\right ) - 2 \,{\left (16657 \, x^{2} + 21843 \, x + 7148\right )} \sqrt{5 \, x + 3} \sqrt{-2 \, x + 1}}{8 \,{\left (45 \, x^{3} + 87 \, x^{2} + 56 \, x + 12\right )}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [B] time = 2.58256, size = 427, normalized size = 3.71 \begin{align*} -\frac{363}{16} \, \sqrt{70} \sqrt{10}{\left (\pi + 2 \, \arctan \left (-\frac{\sqrt{70} \sqrt{5 \, x + 3}{\left (\frac{{\left (\sqrt{2} \sqrt{-10 \, x + 5} - \sqrt{22}\right )}^{2}}{5 \, x + 3} - 4\right )}}{140 \,{\left (\sqrt{2} \sqrt{-10 \, x + 5} - \sqrt{22}\right )}}\right )\right )} - \frac{121}{10} \, \sqrt{10}{\left (\frac{\sqrt{2} \sqrt{-10 \, x + 5} - \sqrt{22}}{\sqrt{5 \, x + 3}} - \frac{4 \, \sqrt{5 \, x + 3}}{\sqrt{2} \sqrt{-10 \, x + 5} - \sqrt{22}}\right )} - \frac{847 \,{\left (9 \, \sqrt{10}{\left (\frac{\sqrt{2} \sqrt{-10 \, x + 5} - \sqrt{22}}{\sqrt{5 \, x + 3}} - \frac{4 \, \sqrt{5 \, x + 3}}{\sqrt{2} \sqrt{-10 \, x + 5} - \sqrt{22}}\right )}^{3} + 1960 \, \sqrt{10}{\left (\frac{\sqrt{2} \sqrt{-10 \, x + 5} - \sqrt{22}}{\sqrt{5 \, x + 3}} - \frac{4 \, \sqrt{5 \, x + 3}}{\sqrt{2} \sqrt{-10 \, x + 5} - \sqrt{22}}\right )}\right )}}{2 \,{\left ({\left (\frac{\sqrt{2} \sqrt{-10 \, x + 5} - \sqrt{22}}{\sqrt{5 \, x + 3}} - \frac{4 \, \sqrt{5 \, x + 3}}{\sqrt{2} \sqrt{-10 \, x + 5} - \sqrt{22}}\right )}^{2} + 280\right )}^{2}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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